public static int doSomething() {
int i = 0;
try {
i = 1;
System.out.print("a");
return i;
}
catch (Exception e) {
i = 2;
System.out.print("b");
return i;
}
finally {
i = 3;
System.out.print("c");
return i;
}
} // end
return ?
return 3 ! and print "ac".
This code behave like the finally block is an inside method:
public static int doSomething() {
int i = 0;
try {
i = 1;
System.out.print("a");
{ // finally block
int another_i = 3;
System.out.print("c");
return another_i;
}
return i;
}
catch (Exception e) {
i = 2;
System.out.print("b");
{ // finally block
int another_i = 3;
System.out.print("c");
return another_i;
}
return i;
}
} // end
...
So, and if there is no return in finally block.
public static int doSomething() {
int i = 0;
try {
i = 1;
System.out.print("a");
return i;
}
catch (Exception e) {
i = 2;
System.out.print("b");
return i;
}
finally {
i = 3;
System.out.print("c");
// return i;
}
} // end
It return 1 and print "ac".
Behave like that:
public static int doSomething() {
int i = 0;
try {
i = 1;
System.out.print("a");
{ // finally block
int another_i = 3;
System.out.print("c");
}
return i;
}
catch (Exception e) {
i = 2;
System.out.print("b");
{ // finally block
int another_i = 3;
System.out.print("c");
}
return i;
}
} // end
The try-catch-finally doesn't really behave as first expected.
See
Java Hall Of Shameand
finally.